>
From
Your
Code
();
Submit a quote
Previous quote
Next quote
Source code
quote in
PHP
n°
181
14 June, 2014 at 07:30
$query = "SELECT * FROM myTable where name!='' and name!=NULL and isnull(name) !=1";
Check similar quotes
But why ?
Yet it works !
Share this quote
Facebook
Twitter
E-mail
Install