>FromYourCode();

Source code quote in PHP184

 July 01, 2014 am31 05:21
foreach( $d->params->sources as &$source )
{
    $src = current(explode( "/", is_array( $source->source ) ? $source->source[1] : $source->source ));
    foreach( $source->fields as $k => &$field )
        $field->source = $m->source->fields[$k];
}

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